Power Factor Correction: Stop Paying Utility Penalties Every Month

Industrial electrical room: the main switchboard with an automatic capacitor bank shown open with its controller and capacitor cans, a motor control centre and motors, the utility meter on the wall.

Your monthly hydro bill may already charge you for poor power factor, even without a separate line item: some distributors bill demand on kVA, which rises as power factor falls. If your facility runs motors, compressors, chillers, or VFDs, you could be paying thousands in unnecessary surcharges every year. Here's what power factor actually is, why the utility penalizes you for it, and how a capacitor bank can pay for itself.

What Is Power Factor?

Power factor is the ratio of real power (kW - the power that actually does useful work) to apparent power (kVA - the total power the utility must deliver to your facility).

Term Unit What It Represents Analogy
Real PowerkWUseful work - running motors, heating, lightingThe beer in your glass
Reactive PowerkVARMagnetizing current - sustains motor fields, transformer coresThe foam on top
Apparent PowerkVATotal power the utility delivers (kW + kVAR combined)The entire glass (beer + foam)
Power FactorratioPF = kW / kVA (ratio, 0 to 1.0)How much of the glass is beer
PF = kW ÷ kVA
A power factor of 1.0 means 100% of the power delivered is doing useful work. A power factor of 0.70 means the utility is delivering 43% more current than you're actually using - and they charge you for it.

Why Do Utilities Penalize Low Power Factor?

When your power factor drops, the utility must supply more current to deliver the same real power. This extra current:

  • Overloads their transformers and distribution lines
  • Increases I²R losses in their cables (more heat, more waste)
  • Reduces available capacity for other customers
  • Forces them to upsize infrastructure sooner

Ontario distributors differ: Hydro One bills delivery on 90% of peak kVA when PF drops below 0.90, while Toronto Hydro bills its demand classes on kVA demand (not kW) - meaning low PF directly inflates your demand charges. Check your distributor's tariff.

Penalty Calculation Example

Parameter Before Correction After Correction
Real Power (kW)500 kW500 kW
Power Factor0.720.96
Apparent Power (kVA)694 kVA521 kVA
kVA Demand Charge (illustrative @$12/kVA)$8,328/mo$6,252/mo
Monthly Savings$2,076/month = $24,912/year

How Power Factor Correction Works

The most common correction method is installing capacitor banks. Capacitors generate reactive power (kVAR) locally, offsetting the reactive power demanded by inductive loads (motors, transformers). This reduces the total current the utility needs to supply.

Correction Method Best For Typical Cost
Fixed Capacitor BankConstant loads (fans, pumps running 24/7)Lower cost
Automatic Capacitor BankVariable loads (manufacturing, commercial)Moderate cost
Active Harmonic FilterVFD-heavy facilities with harmonic issuesHigher cost
Synchronous CondenserLarge industrial plants (5MW+)Highest cost

Sizing the Capacitor Bank

To correct from PF1 to PF2, the required kVAR is:

kVAR = kW × (tan θ₁ - tan θ₂)

Example: Correct 500 kW from PF 0.72 to 0.96:
θ₁ = arccos(0.72) = 43.9° → tan(43.9°) = 0.964
θ₂ = arccos(0.96) = 16.3° → tan(16.3°) = 0.292
kVAR = 500 × (0.964 - 0.292) = 336 kVAR capacitor bank required

A capacitor bank supplies the reactive power the motors need

The article’s 500 kW example on a typical industrial service, not a design. Triangle drawn to scale.

A capacitor bank supplies the reactive power the motors needAn industrial electrical room: the utility meter, a three-section switchboard, an automatic capacitor bank shown open with its power-factor controller reading 0.96, step contactors and capacitor cans, a motor control centre and two motors. Above, a power triangle drawn to scale for 500 kW: at a power factor of 0.72 the apparent power is 694 kVA; capacitors supplying 336 kVAR shorten the reactive side so the apparent power falls to 521 kVA at a power factor of 0.96.0.96POWER TRIANGLE · 500 KW, DRAWN TO SCALEReal power500 kWunchangedApparent power, PF 0.72694 kVAbeforeReactive power before500 × 0.964 kVARtan 43.9°Capacitor bank− 336 kVAR500 × (0.964 − 0.292)Apparent power, PF 0.96521 kVAafterUtility meterAuto capacitor bankMCCINDUCTIVE LOADS12345

Electrical points

  1. Utility meter: some distributors bill demand on kVA: Hydro One bills delivery on 90 % of peak kVA below PF 0.90; Toronto Hydro bills its demand classes on kVA.

  2. Switchboard: at PF 0.72 it carries 694 kVA for 500 kW of work; at 0.96, 521 kVA.

  3. Automatic capacitor bank: switches capacitor steps to follow variable loads; kVAR = kW × (tan θ₁ − tan θ₂) = 500 × (0.964 − 0.292) = 336 kVAR.

  4. Inductive loads: motors and transformers need magnetizing (reactive) current; the capacitors supply it locally.

  5. Power triangle: PF = kW ÷ kVA; target 0.95–0.97, not 1.0: over-correction to a leading PF raises voltage and can unsettle generators.

Run a harmonic study before adding capacitors where VFDs or other non-linear loads are present (resonance); discharge to 50 V or less within 1 min after disconnection. Rule 26-222

  • Real power (kW)
  • Apparent power before (kVA)
  • Apparent power after (kVA)
  • kVAR supplied by the capacitors
Figure 1. Capacitors supply the motors’ reactive power on site, so the utility delivers less kVA for the same kW.Sources: The article’s 500 kW example · OESC Rule 26-222 (CSA C22.1:24) · Hydro One and Toronto Hydro tariffs

Figure 1. A capacitor bank supplies the reactive power the motors need

Installation Considerations

  • Harmonic resonance: Capacitors + system inductance can create resonance at harmonic frequencies. Always perform a harmonic study before installing capacitor banks in facilities with VFDs or non-linear loads
  • Leading power factor: Over-correction (PF > 1.0 leading) can cause voltage rise and generator instability. Target 0.95-0.97, not 1.0
  • Switching transients: Energizing large capacitor banks creates inrush currents and voltage transients. Use pre-insertion resistors or controlled switching contactors
  • OESC Rule 26-222 (capacitors): A discharge circuit must reduce the residual voltage to 50 V or less within 1 min after disconnection (within 5 min for capacitors rated over 750 V); based on CSA C22.1:24, Rule 26-222

ROI - When Does It Pay For Itself?

Facility Size Typical Annual Penalty Correction Cost Payback Period
Small commercial (100 kW)Lower; depends on tariff and measured PFSmall bankSite-specific; confirm with a bill review
Medium industrial (500 kW)Moderate; depends on tariff and measured PFAutomatic bankSite-specific; confirm with a bill review
Large industrial (2 MW)Higher; depends on tariff and measured PFLarger automatic bankSite-specific; confirm with a bill review

Frequently Asked Questions

What is power factor?

The ratio of real power (kW) to apparent power (kVA). Low PF wastes utility capacity. Hydro One bills on 90% of peak kVA below 0.90; Toronto Hydro bills demand on kVA.

How much does a PF penalty cost?

It depends on facility size, tariff and measured power factor. See our load calculation guide for demand analysis.

How fast does correction pay for itself?

Payback depends on the tariff, measured power factor and bank cost; a bill review and a quote will show it. Watch for harmonic resonance issues.

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